What will be the phenotypic ratio of offsprings from a marriage between colour blind father and Career mother

When a color-blind father (who carries a recessive X-linked trait for color blindness) and a carrier mother

When a color-blind father (who carries a recessive X-linked trait for color blindness) and a carrier mother (who has one normal X chromosome and one X-linked allele for color blindness) have children, it's possible to predict the phenotypic ratio of their offspring.

Let's use "C" to represent the normal vision allele and "c" to represent the allele for color blindness. The mother's genotype is X^C X^c, and the father's genotype is X^c Y.

X^C X^c (female with normal vision)
X^C X^c (female with normal vision)
X^C Y (male with normal vision)
X^C Y (male with normal vision)
In this case, all their children will have normal vision because they inherit a normal X chromosome from their mother. The father's Y chromosome does not carry the gene for color vision. Therefore, the phenotypic ratio of their offspring will be 100% for normal vision. So, in this scenario, the phenotypic ratio of their offspring would be 4:0 (4 with normal vision, 0 with color blindness).