What will be the phenotypic ratio of offsprings from a marriage between colour blind father and normal mother

The phenotypic ratio of offspring from a marriage between a color-blind father (recessive X-linked trait) and a normal mother (with two normal X chromosomes)

The phenotypic ratio of offspring from a marriage between a color-blind father (recessive X-linked trait) and a normal mother (with two normal X chromosomes) will depend on the genetic inheritance pattern associated with the X-linked color blindness trait.

Color blindness is typically an X-linked recessive trait. In this case:

The father (XY) has one X chromosome carrying the color-blind allele and one Y chromosome.
The mother (XX) has two normal X chromosomes.
The possible combinations for their offspring are as follows:

Sons (XY):

Sons inherit one X chromosome from the mother and one Y chromosome from the father. They will not have the X-linked color blindness trait because they do not inherit the color-blind allele from their father.

Daughters (XX):

Daughters inherit one X chromosome from the mother and one X chromosome from the father. Since they inherit a normal X chromosome from the mother and a normal X chromosome from the father, they will not have the X-linked color blindness trait either. So, in this case, all of the offspring (sons and daughters) will have normal color vision, and the phenotypic ratio is: 100% normal color vision (no color-blind offspring) The phenotypic ratio for this particular mating is 100% normal color vision in all the offspring, as the color blindness trait is recessive and the father passes on a Y chromosome to his sons, ensuring they do not inherit the trait.